NCERT Solutions for Class 9 Science Chapter 9
Force and Laws of Motion
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-128
Questions No-10
Using a horizontal force of 200 N, we intend to move a wooden cabinet across a floor at a constant velocity. What is the friction force that will be exerted on the cabinet?
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To determine the friction force exerted on the wooden cabinet, when a horizontal force of 200 N is applied to move it at a constant velocity, we’ll first consider the concept of static friction.
When an object is moving at a constant velocity, the force applied (200 N in this case) is equal to the force of friction acting against it.
Therefore, the friction force exerted on the cabinet will be equal to the applied force, which is 200 N. This friction force counteracts the applied force, allowing the cabinet to move at a constant velocity across the floor.
A force of 200 N is applied in the forward direction. Thus, from Newton’s third
law of motion, an equal amount of force will act in the opposite direction. This
opposite force is the fictional force exerted on the cabinet. Hence, a frictional
force of 200 N is exerted on the cabinet.
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