NCERT Solution for Class 10 Science Chapter 5
Periodic Classification of Elements
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Intext Questions
Page No-1
Questions No-85
Use Mendeleev’s Periodic Table to predict the formulae for the oxides of the following elements: K, C, AI, Si, Ba.
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K is in group 1. Therefore, the oxide will be K₂O.
C is in group 4. Therefore, the oxide will be CO₂.
Al is in group 3. Therefore, the oxide will be Al₂O₃.
Si is in group 4. Therefore, the oxide will be SiO₂.
Ba is in group 2. Therefore, the oxide will be BaO.
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K Valancy 1
O Valancy 2
So, it will be K2O
K₂O CO₂ Al₂O₃
SiO₂.
BaO.
K2O
CO2
Al2O3
SiO2
BaO
Use crisscross method to give answers.
Al is in group 3.
O is in group 16
Therefore, the oxide will be Al₂O₃.
(i) The general formula for oxides of 1st, 2nd, third and 4th group are R2O, RO, R2O3 and RO2 respectively in the Mendeleev’s Periodic Table, where R denotes the element.
(ii) Since, Potassium (K) belongs to 1st group, thus, formula of its oxide would be K2O.
(iii) Barium (Ba) belongs to 2nd group, thus formula of its oxide would be BaO.
(iv) Aluminium (Al) belongs to the 3rd group, thus, formula of its oxide would be Al2O3.
(v) Carbon (C) and Silicon (Si) belong to the 4th group, thus, formula of its oxide would be CO2 and SiO2 respectively.
(vi) Thus, formula of oxides of the given elements would be K2O, CO2, Al2O3, SiO2 and BaO; respectively.
(i) The general formula for oxides of 1st, 2nd, third and 4th group are R₂O, RO, R₂O₃ and RO₂ respectively in the Mendeleev’s Periodic Table, where R denotes the element.
(ii) Since, Potassium (K) belongs to 1st group, thus, formula of its oxide would be K₂O.
(iii) Barium (Ba) belongs to 2nd group, thus formula of its oxide would be BaO.
(iv) Aluminium (Al) belongs to the 3rd group, thus, formula of its oxide would be Al₂O₃.
(v) Carbon (C) and Silicon (Si) belong to the 4th group, thus, formula of its oxide would be CO₂ and SiO₂ respectively.
(vi) Thus, formula of oxides of the given elements would be K₂O, CO₂, Al₂O₃, SiO₂ and BaO.