Two students A and B calculate the charge flowing through a circuit. A concludes that 300 C of charge flows in 1 minute. B concludes that 3.125 x 10¹⁹ electrons flow in 1 second. If the current measured in the circuit is 5 A, then the correct calculation is done by
Current I is given by I = Q/t. Student A: Q = 300C. t = 60s, so I = 300/60 = 5A(correct).
Student B: Q = (3.125 × 10¹⁹) × (1.6 × 10⁻¹⁹) = 5C, t = Is, so I = 5/1 = 5A (correct).
thus, both A and B are correct. Answer: (c) Both A and B.
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To check who made the correct calculation, let’s compare both answers using the current and time. 1
A’s calculation:
The current
I. = 5A, and the charge flowing in 1 minute (60 seconds) is given by:
Q = I × t = 5A × 60s = 300 C
So, A’s calculation is correct.
2. B’s calculation:
The number of electrons flowing per second can be calculated by:
Number of electrons = Q/e
where e = 1.6 ×10⁻¹⁹C (charge of one electron) and
Q = 5C/s.
Number of electrons = 5/1.6 × 10⁻¹⁹ 3.125 × 10¹⁹ electrons/s
So, B’s calculation is also correct.
Thus, the correct answer is (c) both A and B.
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https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
Current is given by I = Q/t
For A: I = 300/60 = 5A (correct).
For B: Charge Q = (3.125 10) (1.6 10) = 5C, so I = 5A (correct).
Thus, both A and B are correct. Answer: (c) both A and B.
For more visit here:
https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/