The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous valiue, the new time period will. become

According to Kepler’s law of periods, the square of the orbital period of a planet (T²) is directly proportional to the cube of the semi-major axis of its orbit (r³). This relationship can be expressed as the ratio of the periods and radii of two planets. For example, if one planet’s radius is four times that of another, the ratio of their periods squared is equal to the ratio of their radii cubed. This leads to the conclusion that the period of the second planet is eight times longer than the first.
Thus, if the first period is 5 hours, the second period will be 40 hours.
According to Kepler’s law of periods,
T² ∝ r³
(T₂/T₁)² = (r₂/r₁)³ = (4/1)³ = 64
T₂ = 8T₁ = 8 x 5 = 40 h.