The taxi fare in a city is as follows: For the first kilometre, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.

Given that: Distance travelled = x km and total fare = ₹ y
Total fare = Fare for first km + Fare for remaining distance
Therefore, the equation: y = 8 + 5 × (x – 1) ⇒ y = 5x +3
For the graph:
Putting x = 1, we have, y = 5 × 1 + 3 = 8
Putting x = 2, we have, y = 5 × 2 + 3 = 13
Putting x = 3, we have, y = 5 × 3 + 3 = 18
Hence, A(1, 8), B(2, 13) and C[3, 18) are solutions of the equation.