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The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

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NCERT Solutions for Class 10 Maths Chapter 5
Important NCERT Questions
Arithmetic Progression
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 5.3
Page No:113
Questions No:5

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2 Answers

  1. Here, a = 5, a_n = 45 and S_n = 400.
    The sum of n terms of an AP is given by
    S_n = n/2[a + a_n]
    ⇒ 400 = n/2[5 + 45]
    ⇒ 400 = 25n
    ⇒ n = 400/25 = 16
    a_n = a + (n – 1)d
    ⇒ 45 = 5 + (16 – 1)d
    ⇒ 40 = 15d
    ⇒ d = 40/15 = 8/3
    Hence, the number of term are 16 and the common difference is 8/3.

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  2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-5/

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