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The diameter of the moon is approximately one fourth the diameter of the earth. Given that the moon and earth are both roughly spherical, find the ratio of their surface areas.

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The ratio of their diameters and radii is 1 : 4. Since the surface area of a sphere is proportional to the square of its radius, the ratio of their surface areas is 1² : 4² = 1 : 16.

Cbse Class 9 Maths Ganita Manjari Part 2 Solutions
Class 9 maths ganita manjari part 2 chapter 14 question answer

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  1. Let the diameter of the Earth be D and the diameter of the Moon be D/4, meaning their radii are in the ratio r_moon / r_earth = 1 / 4. The surface area of a sphere is given by SA = 4πr². Therefore, the ratio of their surface areas is SA_moon / SA_earth = (r_moon / r_earth)² = (1/4)² = 1 / 16, which is 1 : 16.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/

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