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Laksh
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Asked: 2020-12-30T04:18:15+00:00 In:

Subba Rao started work in 1995 at an annual salary of rupay 5000 and received an increment of rupay 200 each year. In which year did his income reach ` 7000?

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NCERT Solutions for Class 10 Maths Chapter 5
Important NCERT Questions
Arithmetic Progression
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 5.2
Page No:107
Questions No:19

2020-2021arithmetic progressioncbsechapter 5class10mathematicsncert
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    2 Answers

    1. Best Answer

      Starting salary = a = Rs 5000 annual increment (common difference) = d = Rs 200
      Let, after n years, his salary become Rs 7000.
      Therefore, a_n = 7000
      ⇒ a + (n -1)d = 7000
      ⇒ 5000 + (n – 1)(200) = 7000
      ⇒ (n -1)(200) = 2000
      ⇒ n – 1 = 10 ⇒ n = 11
      Hence, in 11th year his salary become Rs 7000.

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    2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-5/

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