NCERT Solutions for Class 10 Maths Chapter 5

Important NCERT Questions

Arithmetic Progression

NCERT Books for Session 2022-2023

CBSE Board and UP Board Others state Board

EXERCISE 5.2

Page No:107

Questions No:19

# Subba Rao started work in 1995 at an annual salary of rupay 5000 and received an increment of rupay 200 each year. In which year did his income reach ` 7000?

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Starting salary = a = Rs 5000 annual increment (common difference) = d = Rs 200

Let, after n years, his salary become Rs 7000.

Therefore, a_n = 7000

⇒ a + (n -1)d = 7000

⇒ 5000 + (n – 1)(200) = 7000

⇒ (n -1)(200) = 2000

⇒ n – 1 = 10 ⇒ n = 11

Hence, in 11th year his salary become Rs 7000.