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Subba Rao started work in 1995 at an annual salary of rupay 5000 and received an increment of rupay 200 each year. In which year did his income reach ` 7000?

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NCERT Solutions for Class 10 Maths Chapter 5
Important NCERT Questions
Arithmetic Progression
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 5.2
Page No:107
Questions No:19

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  1. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-5/

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  2. Starting salary = a = Rs 5000 annual increment (common difference) = d = Rs 200
    Let, after n years, his salary become Rs 7000.
    Therefore, a_n = 7000
    ⇒ a + (n -1)d = 7000
    ⇒ 5000 + (n – 1)(200) = 7000
    ⇒ (n -1)(200) = 2000
    ⇒ n – 1 = 10 ⇒ n = 11
    Hence, in 11th year his salary become Rs 7000.

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