The solutions are:
a. 8 – 13 = –5.
b. (–8) – (13) = –21.
c. (–13) – (–8) = –5.
d. (–13) + (–8) = –21.
Each calculation shows integer addition and subtraction.
Class 6 Mathematics Ganita Prakash The Other Side of Zero
Class 6 Mathematics Chapter 10 The Other Side of Zero question answer
The solutions to these problems demonstrate integer operations:
a. 8 – 13 = –5. Subtracting a larger number gives a negative result.
b. (–8) – (13) = –21. Subtraction combines the negatives, extending the negative value.
c. (–13) – (–8) = –5. Subtracting a negative is equivalent to adding a positive.
d. (–13) + (–8) = –21. Adding two negatives deepens the negative result. These examples illustrate key integer rules.
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