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Home/ Questions/Q 2180
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Anand Singh
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Anand Singh
Asked: November 5, 20202020-11-05T03:22:45+00:00 2020-11-05T03:22:45+00:00In: Class 9

Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m × 3 m?

  • 9

NCERT Solutions for Class 9 Maths Chapter 13
Important NCERT Questions
Surface Areas and Volumes
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 13.1
Page No:213
Questions No:8

2020-2021cbsechapter 13class 9mathematicsncertsurface areas and volumes
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    1. Saarya Anand
      2021-07-30T11:30:58+00:00Added an answer on July 30, 2021 at 11:30 am

      Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-13/

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      manoj koshal
      2023-03-03T09:14:11+00:00Added an answer on March 3, 2023 at 9:14 am

      Length of shelter l = 4 m, breadth b = 3 m and height h = 2.5 m
      Area of four walls and top of shelter = total area of shelter – area of floor = 2(lb + bh + hl) – lb
      = 2(4 × 3 + 3 × 2.5 × 4) – 4 × 3 m²
      = 2(12 + 7.5 + 10) – 12 m²
      = 2(29.5) – 12 m²
      = 59 – 12 = 47 m²
      Hence, 47 m² tarpaulin is required to make this shelter.

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