NCERT Solutions for Class 9 Maths Chapter 13

Important NCERT Questions

Surface Areas and Volumes

NCERT Books for Session 2022-2023

CBSE Board, UP Board and Other state Boards

EXERCISE 13.1

Page No:213

Questions No:8

# Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m × 3 m?

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Length of shelter l = 4 m, breadth b = 3 m and height h = 2.5 m

Area of four walls and top of shelter = total area of shelter – area of floor = 2(lb + bh + hl) – lb

= 2(4 × 3 + 3 × 2.5 × 4) – 4 × 3 m²

= 2(12 + 7.5 + 10) – 12 m²

= 2(29.5) – 12 m²

= 59 – 12 = 47 m²

Hence, 47 m² tarpaulin is required to make this shelter.