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Kinetic energy of particles of mass 10 g and 40 g is same, the ratio of their linear momentum is

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Linear momentum is the measure of an object’s motion in a straight line. It is calculated as the product of an object’s mass and velocity. Represented as p = m * v, linear momentum is a vector quantity and is conserved in isolated systems during collisions or interactions.

Chapter 5 of Class 11 Physics focuses on work energy and power. It explains the calculation of work done by a force energy transformations the law of conservation of energy and forms of energy like kinetic and potential. Power is introduced as the rate of doing work.

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  1. To find the ratio of the linear momentum of two particles with the same kinetic energy, we can use the formulas for kinetic energy and momentum.

    Step 1: Write the formula for kinetic energy

    The kinetic energy (K.E.) is given by:

    K.E. = (1/2) m v²

    Where:
    – m = mass
    – v = velocity

    Step 2: Set the kinetic energies equal

    Let:
    – m₁ = 10 g = 0.01 kg
    – m₂ = 40 g = 0.04 kg

    Since their kinetic energies are the same:

    (1/2) m₁ v₁² = (1/2) m₂ v₂²

    Cancelling (1/2) from both sides gives:

    m₁ v₁² = m₂ v₂²

    Step 3: Express velocity in terms of momentum

    The momentum (p) is given by:

    p = mv

    From the above equation:

    0.01 v₁² = 0.04 v₂²

    Rearranging gives us:

    v₁²/v₂² = 0.04/0.01
    v₁²/v₂² = 4

    Step 4: Find the ratio of velocities

    Taking the square root of both sides:

    v₁/v₂ = 2

    Step 5: Calculate the ratio of momenta

    Now, using the definition of momentum:

    p₁ = m₁ v₁
    p₂ = m₂ v₂

    The ratio of their momenta is:

    p₁/p₂ = (m₁ v₁) / (m₂ v₂)
    p₁/p₂ = (0.01 v₁) / (0.04 v₂)

    Substituting the ratio of velocities:

    p₁/p₂ = (0.01 * 2v₂) / (0.04 v₂)
    p₁/p₂ = (0.02 / 0.04)
    p₁/p₂ = 1/2

    Final Answer:
    The ratio of their linear momentum is 1/2.

    Click here for more:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-5/

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