NCERT Solutions for Class 10 Maths Chapter 8
Important NCERT Questions
Introduction Trigonometry
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 8.1
Page No:181
Questions No:9
(i) sin A cos C + cos A sin C
(ii) cos A cos C – sin A sin C
Given that: tan A = 1/√3
Let tan A = 1k/√3, where k is a real number.
In △ABC, by Pythagoras theorem, we have
AC² = BC²+AB²
= (1k)²+(V3k)²
= k²+3k² = 4k²
⇒ AC = √(4k)² = 2k
(i) sin A cos C+cos A sin C
= 1/2 × 1/2 + √3/2 × √3/2 = 1/4 + 3/4 = (1+3)/4 = 4/4 = 1
(ii) cos A cos C sin A sin C
= √3/2 × 1/2 – 1/2 × √3/2 = √3/4 – √3/4 = 0
For better understanding of above question you can see here😃👇
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