Find the area of the shaded region. (Use π = 3.14)
NCERT Math’s Class 10 Chapter 12
Page No. 237
Exercise 12.3
Question No. 13
In Figure, a square OABC is inscribed in a quadrant OPBQ. If OA = 20 cm,
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In A0AB,
OB² = OA² + AB² ⇒ OB² = (20)² + (20)² ⇒ OB² = 400+ 400
⇒ OB² = 800 ⇒ OB = √800
Radius of quadrant = 20√2 cm
Area of quadrant
= 90°/360° × πr² = 1/4 × π(20√2)²
= 1/4 × 3.14 × 20√2 × 20√2 = 628 cm²
Area of square
= (Side)² = (20)² = 400 cm²
Area of shaded region = Area of quadrant – Area of square
= 628 – 400 = 228 cm²