Find the area of the shaded region. (Use π = 3.14)

NCERT Math’s Class 10 Chapter 12

Page No. 237

Exercise 12.3

Question No. 13

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In A0AB,

OB² = OA² + AB² ⇒ OB² = (20)² + (20)² ⇒ OB² = 400+ 400

⇒ OB² = 800 ⇒ OB = √800

Radius of quadrant = 20√2 cm

Area of quadrant

= 90°/360° × πr² = 1/4 × π(20√2)²

= 1/4 × 3.14 × 20√2 × 20√2 = 628 cm²

Area of square

= (Side)² = (20)² = 400 cm²

Area of shaded region = Area of quadrant – Area of square

= 628 – 400 = 228 cm²