Can you provide me video explanation for class 9 ncert math’s chapter 6.
NCERT CLASS 9 Chapter 6 Lines and angles
Page No. 104
Exercise 6.2
Question No. 2
In Fig. 6.29, if AB || CD, CD || EF and y : z = 3 : 7, find x.
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Given: y:z = 3:7
Let, y = 3k, therefore z = 7k
y = ∠1 = 3k [∵ Vertically Opposite Angles]
Given: CD||EF,
Therefore,
∠1 + z = 180° [∵ Sum of co-interior angles]
⇒ 3k + 7k = 180°
⇒ 10k = 180°
⇒ k = 180°/10 = 18°
Hence, z = 7k = 7 × 18° = 126°
Given that : AB||CD and CD||EF, therefore AB||EF
⇒ x = z = 126° [∵ Alternate Angles]