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Mridul Gupta
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Asked: 2023-02-23T08:44:13+00:00 In:

In Fig. 12.30, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, fiIn Fig. 12.30, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm,

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In Fig. 12.30, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, fiIn Fig. 12.30, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm,

Find the area of the
(i) quadrant OACB,
(ii) shaded region.
NCERT Class 10 Chapter 12
Page No. 237
Exercise 12.3
Question No. 11

chapter 12mathsncert class 10
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    1. Best Answer
      In Fig. 12.30, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, fiIn Fig. 12.30, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm,

      Radius of circle = 7 cm
      Area of one circular design
      πr² = π(7)² = 22/7 × 7 × 7 = 154 cm²
      Side of square = 42 cm
      Area of squre = (Side)² = (42)² = 1764cm²
      The area of the remaining portion = Area of square – Area of 9 circular designs
      = 1764 – 9 × 154 = 196 1386 = 378 cm²

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