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Home/ Questions/Q 1726
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Laksh
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Laksh
Asked: December 26, 20202020-12-26T04:23:48+00:00 2020-12-26T04:23:48+00:00In: Class 10 Maths

How many terms of the AP : 9, 17, 25, . . . must be taken to give a sum of 636?

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NCERT Solutions for Class 10 Maths Chapter 5
Important NCERT Questions
Arithmetic Progression
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 5.3
Page No:107
Questions No:4

2020-2021arithmetic progressioncbsechapter 5class10mathematicsncert
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    1. Aadhila Singh
      2021-07-29T06:11:07+00:00Added an answer on July 29, 2021 at 6:11 am

      Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-5/

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      surya jha
      2023-01-30T10:49:12+00:00Added an answer on January 30, 2023 at 10:49 am

      Here, a = 9, d = 17 – 9 = 8 and S_n = 636.
      The sum of n terms of an AP is given by
      S_n = n/2[2a + (n -1)d]
      ⇒ 636 = n/2[2(9) + (n -1)(8)]
      ⇒ 636 = n[9 + 4n – 4]
      ⇒ 4n² + 5n – 636 = 0
      ⇒ 4n² + 53n – 48n – 636 = 0
      ⇒ n(4n + 53) – 12(4n + 53) = 0
      ⇒ (n – 12)(4n + 53) = 0
      ⇒ n – 12 = 0 [∵ sn + 53 ≠ 0 as n ≠ – 53/4]
      ⇒ n = 12
      Hence, 12 terms of the AP: 9, 17, 25 … must be taken to get the sum 636.

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