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Rajshekhar
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Asked: 2024-11-22T09:22:52+00:00 In:

How many rounds does the number 5683 take to reach the Kaprekar constant?

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Starting with 5683, arrange digits in descending and ascending order. Subtract smaller from larger repeatedly:
8653 − 3568 = 5085
8550 − 0558 = 7992
9972 − 2799 = 6174.
It takes three rounds.

Class 6 Mathematics Chapter 3 Number Play question answer

Class 6 NCERT Ganita Prakash Chapter 3 Number Play

class 6 maths chapter 3 number play figure it out solutionsclass 6 maths number play chapter 3 mcqclass 6 maths number play extra questionsrounds does the number 5683 take to reach the kaprekar constant
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    1 Answer

    1. For 5683, following the Kaprekar process:
      1. Arrange digits: 8653 (largest) and 3568 (smallest). Subtract: 8653 − 3568 = 5085.
      2. Repeat: 8550 − 0558 = 7992.
      3. Finally: 9972 − 2799 = 6174.
      It takes three rounds to reach the Kaprekar constant, 6174. This process consistently converges to 6174 for any 4-digit number (with non-identical digits), showcasing Kaprekar’s mathematical discovery.

      For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
      https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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