Starting with 5683, arrange digits in descending and ascending order. Subtract smaller from larger repeatedly:
8653 − 3568 = 5085
8550 − 0558 = 7992
9972 − 2799 = 6174.
It takes three rounds.
Class 6 Mathematics Chapter 3 Number Play question answer
Class 6 NCERT Ganita Prakash Chapter 3 Number Play
For 5683, following the Kaprekar process:
1. Arrange digits: 8653 (largest) and 3568 (smallest). Subtract: 8653 − 3568 = 5085.
2. Repeat: 8550 − 0558 = 7992.
3. Finally: 9972 − 2799 = 6174.
It takes three rounds to reach the Kaprekar constant, 6174. This process consistently converges to 6174 for any 4-digit number (with non-identical digits), showcasing Kaprekar’s mathematical discovery.
For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/