Radius of circular sheet (R) = 14 cm and Radius of smaller circle (r) = 3.5 cm
Length of rectangle (l) = 3 cm and breadth of rectangle (b) = 1 cm
According to question,
Area of remaining sheet=Area of circular sheet– (Area of two smaller circle + Area
of rectangle)
= πR² – [2(πR²) + (lxb)
= 22/7x14x14 – [(2×22/7×3.5×3.5)-(3×1)]
= 22 x 14 x 2 – [44 x 0.5 x 3.5 + 3]
= 616 – 80
= 536 cm²
Therefore the area of remaining sheet is 536 cm².

Class 7 Maths Chapter 11 Exercise 11.3

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