NCERT Solutions for Class 9 Maths Chapter 2
Important NCERT Questions
Polynomials
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 2.4
Page No:44
Questions No:3 part:1
Find the value of k, if x – 1 is a factor of p(x) in the following cases: p(x) = x² + x + k
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(i) p(x) = x² + x + k
Putting x – 1 = 0, we get, x = 1
Using remainder theorem, when p(x) = x² + x + k is divided by x – 1, remainder is given by p(1)
= (1)² + (1) + k
= 2 + k
Since x – 1 is a factor of p(x), hence remainder p(1) = 0
⇒ 2 + k = 0
⇒ k = -2
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