Find the value of k, if x – 1 is a factor of p(x) in the following cases: p(x) = 2x² + kx + √2

(ii) p(x) = 2x² + kx + √2
Putting x – 1 = 0, we get, x = 1
Using remainder theorem, when p(x) = 2x² + kx + √2 is divided by x – 1, remainder is given by p(1)
= 2(1)² + k(1) + √2
= 2 + k + √2
Since x – 1 is a fctor of p(x), hence remainder p(1) = 0
⇒ 2 + k + √2 = 0
⇒ k = -2 – √2