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Naksh Singh
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Asked: 2021-01-02T05:00:40+00:00 In:

Find the sum of the first 40 positive integers divisible by 6.

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NCERT Solutions for Class 10 Maths Chapter 5
Important NCERT Questions
Arithmetic Progression
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 5.3
Page No:113
Questions No:12

2020-2021arithmetic progressioncbsechapter 5class10mathematicsncert
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    2 Answers

    1. Best Answer

      The first 40 positive integers divisible by 6 are 6, 12, 18, …, 240.
      Here, a = 6, d = 12 – 6 = 6 and n = 40.
      The sum of n terms of an AP is Given by
      S_n = n/2[2a + (n -1)d]
      ⇒ S_40 = 10/2[2(6) + (40 -1)(6)]
      = 20[12 + 234]
      = 20(246) = 4920
      Hence, the sum of the first 40 positive integers divisible by 6 is 4920.

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    2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-5/

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