NCERT Solutions for Class 9 Maths Chapter 13
Important NCERT Questions
Surface Areas and Volumes
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 13.8
Page No:236
Questions No:2
Find the amount of water displaced by a solid spherical ball of diameter (i) 28 cm (ii) 0.21 m
Share
(I) Radius of spherical ball r = 28/2 = 14 cm
Volume of water displaced by spherical ball = 4/3πr³
= 4/3 × 22/7 × 14 × 14 × 14 × = 4/3 × 22 × 2 × 14 × 14 = 11498(2/3) cm³
Hence, the volume of water displaced by spherical ball is 11498(2/3) cm³.
(II) Radius of spherical ball r = 0.21/2 = 0.105 m
Volume of water displaced by spherical ball = 4/3πr³
= 4/3 × 22/7 × 0.105 × 0.105 × 0.105 = 4 × 22 × 0.005 × 0.63 × 0.63 = 0.004861 m³
Hence, the volume of water displaced by spherical ball is 0.004861 m³.
Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
Please follow the link to visit website for first and second term exams solutions.
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-13/