Factorise the following: 64a³ – 27b³ – 144a²b + 108ab²

We have, 64a
3
−27b
3
−144a
2
b+108ab
2
=(4a)
3
+(−3b)
3
−36ab(4a−3b)
Using, (a+b)
3
=a
3
+b
3
+3ab(a+b)
=(4a)
3
+(−3b)
3
+3(4a)(−3b)(4a−3b)
=(4a−3b)
3

=(4a−3b)(4a−3b)(4a−3b)