NCERT Solutions for Class 9 Maths Chapter 2
Important NCERT Questions
Polynomials
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 2.5
Page No:49
Questions No:8 part:4
Factorise the following: 64a³ – 27b³ – 144a²b + 108ab²
Share
Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
Please follow the link to visit website for first and second term exams solutions.
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-2/
We have, 64a
3
−27b
3
−144a
2
b+108ab
2
=(4a)
3
+(−3b)
3
−36ab(4a−3b)
Using, (a+b)
3
=a
3
+b
3
+3ab(a+b)
=(4a)
3
+(−3b)
3
+3(4a)(−3b)(4a−3b)
=(4a−3b)
3
=(4a−3b)(4a−3b)(4a−3b)