We apply the standard square identity to this expression. By recognizing that 49x square is (7x) square and 4y square is (2y) square, we can easily write the final factors as (7x + 2y) square.
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We apply the standard square identity to this expression. By recognizing that 49x square is (7x) square and 4y square is (2y) square, we can easily write the final factors as (7x + 2y) square.
This algebraic expression can be factored by identifying the perfect square components within it. The first part of the expression is 49x square, which is equal to (7x) square. The last part of the expression is 4y square, which is equal to (2y) square. The middle value 28xy is two times 7x times 2y. This fits the identity perfectly, resulting in the final answer of (7x + 2y) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/