NCERT Solutions for Class 9 Maths Chapter 11
Important NCERT Questions
Constructions
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 11.2
Page No:195
Questions No:3
Construct a triangle PQR in which QR = 6cm, ∠Q = 60° and PR – PQ = 2cm.
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Steps of construction
(i) Draw a line segment QR = 6 cm.
(ii) At point Q, Using ruler and compass, draw an angle ∠RQX = 60°. Produce XQ to K.
(iii) Taking Q as centre and 2 cm as radius, draw an arc which intersects QK at S.
(iv) Jion SR and draw a perpendicular bisector (MN) of SR, which intersects QX at point P.
(v) join PR. Triangle PQR is the required triangle.
Justification
Point P lies on the perpendicular bisector of SR. So, PS = PR
Here, QS = PS – PQ
⇒ QS = PR – AC [∵ PS = PR]