Rachit Aggarwal
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An object of mass 40 kg is raised to a height of 5 m above the ground. What is its potential energy? If the object is allowed to fall, find its kinetic energy when it is half-way down.

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NCERT Solutions for Class 9 Science Chapter 11
Important NCERT Questions
Work and Energy
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-158
Questions No-10

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2 Answers

  1. The potential energy (PE) of an object at a height above the ground can be calculated using the formula:

    PE = m x g x h

    Where:
    – PE is the potential energy,
    – m is the mass of the object (40 kg),
    – g is the acceleration due to gravity (approximately 9.81 m/s² on Earth,
    – h is the height above the ground (5 m).

    Let’s calculate the potential energy of the object first:

    PE = 40 kg x 9.81 m/s² x 5m
    PE = 1962 J

    Therefore, the potential energy of the object raised to a height of 5 m above the ground is 1962 joules.

    Now, to find the kinetic energy (KE) of the object when it is halfway down (at a height of 2.5 m), we’ll use the principle of conservation of mechanical energy, assuming no air resistance or other non-conservative forces.

    At the midpoint, potential energy is converted entirely into kinetic energy:

    KE = PE_initial – PE_final

    At the midpoint:
    – PE_initial = 1962 J (potential energy at the top)
    – PE_final = 0 J (potential energy at the midpoint when it’s fully converted to kinetic energy)

    KE = 1962 J – 0 J
    KE = 1962 J

    Therefore, when the object is halfway down, its kinetic energy is also 1962 joules.

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  2. Get Hindi Medium and English Medium NCERT Solution for Class 9 Science to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-11/

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