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An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.

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NCERT Solutions for Class 9 Maths Chapter 12
Important NCERT Questions
Heron’s Formula
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 12.1
Page No:203
Questions No:6

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  1. Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-12/

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  2. Perimeter of triangle = 30 cm
    Two sides of triangle b = 12 cm and c = 12 cm.
    Let, the third side = a cm
    We know that the Parimeter of triangle = a + b + c
    ⇒ 30 = a + 12 + 12
    ⇒ 30 – 24 = a
    ⇒ a = 6
    So, the Semi- perimeter of triangle is given by
    S = a + b + c /2 = 30/2 = 15 cm
    Therefore, using Heron’s formula, the area of triangle = √s(s – a)(s – b)(s – c)
    = √15(15 -6)(15 -12)(15 -12)
    = √15(9)(3)(3)
    = 9√15 cm²
    Hence, the area of triangle is 9√15 cm².

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