Amit buys few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not, why? [Hint: The value of g is greater at the poles than at the equator.]

– Acceleration due to Gravity (g) Variation: The value of (g) (acceleration due to gravity) is greater at the poles and slightly lower at the equator due to the Earth’s shape and rotation.

– Earth’s Shape and Gravitational Variation: The Earth is not a perfect sphere but is slightly flattened at the poles and bulging at the equator because of its rotation. This difference in shape influences the distribution of mass, causing variation in gravitational pull at different locations.

– Stronger Gravity at the Poles: At the poles, where the Earth is closer to a spherical shape, the gravitational force (g ) is slightly stronger due to the more direct pull towards the center.

– Weaker Gravity at the Equator: Conversely, at the equator, the gravitational force (g) is slightly weaker due to the centrifugal force caused by the Earth’s rotation, which counteracts some of the gravitational pull.

– Impact on Weight Measurement: When an object, such as gold, is bought at the poles where (g) is stronger and then measured at the equator where (g) is weaker, the weight of the gold will appear slightly lower at the equator. This discrepancy occurs due to the variation in gravitational acceleration between the two locations, affecting the perceived weight of the gold.