NCERT Solutions for Class 10 Maths Chapter 9
Important NCERT Questions
SOME APPLICAT IONS OF TRIGONOMETRY
(Height and Distance)
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 9.1
Page No:213
Questions No:2
A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree.
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Get here all the solutions of class 10 Maths Exercise 9.1
NCERT Solutions for class 10 Maths Exercise 9.1 all questions in Hindi Medium
Let AC is the tree which break at B and the broken part AB become A’B.
In ΔA’BC,
BC/A’C = ten 30⁰
⇒ BC/8 = 1/√3
⇒ BC = 8/√3
and A’C/A’B = cos 30⁰
⇒ 8/A’B = √3/2 ⇒ A’B = 16/√3
Height of the tree
= AC = AB + BC = A’B + BC
= 16/√3 + 8/√3 = 24/√3 = 24√3/3 = 8√3
Hence, the height of the tree 8/√3m.