Home/ Questions/Q 451611
Next
In Process
alok12
  • 1
Poll
Asked: 2025-01-13T09:55:47+00:00 In:

A thin ring of radius 𝑅 and mass 𝑀 rotates about an axis passing through its diameter. What is its moment of inertia?

  • 1

Poll Results

0%MR²
100%1/2MR² ( 1 voter )
0%1/4MR²
0%2MR²
Based On 1 Vote

Participate in Poll, Choose Your Answer.

This question assesses the calculation of the moment of inertia for a thin ring.

Create a series of multiple-choice questions (MCQs) for CBSE Class 11 Physics, Chapter 6: “System of Particles and Rotational Motion,” following the NCERT syllabus for 2024-2025. The questions should focus on key concepts such as center of mass, torque, angular momentum and rotational dynamics. Include a combination of theoretical and numerical problems, ensuring a range of difficulty levels to evaluate students’ conceptual clarity and problem-solving abilities. Ensure that the questions are clearly worded and concise, aligned with NCERT guidelines to provide effective practice and support students in mastering the fundamentals of rotational motion.

chapter 6. system of particles and rotational motionclass 11th physicsclass 11th scienceexercise questionmcq based questionncert solutionshort answer
Share

    1 Answer

    1. The moment of inertia of a thin ring about a diameter is 𝐼 = 1/2MR² , as derived using the perpendicular axis theorem.
      This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational motion. Give answer according to your understanding.

      For more please visit here:
      https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/

      • 1
    Leave an answer

    Leave an answer

    Browse