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A thin ring of radius ๐‘… and mass ๐‘€ rotates about an axis passing through its diameter. What is its moment of inertia?

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Poll Results

0%MRยฒ
100%1/2MRยฒ ( 1 voter )
0%1/4MRยฒ
0%2MRยฒ
Based On 1 Vote

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This question assesses the calculation of the moment of inertia for a thin ring.

Create a series of multiple-choice questions (MCQs) for CBSE Class 11 Physics, Chapter 6: “System of Particles and Rotational Motion,” following the NCERT syllabus for 2024-2025. The questions should focus on key concepts such as center of mass, torque, angular momentum and rotational dynamics. Include a combination of theoretical and numerical problems, ensuring a range of difficulty levels to evaluate students’ conceptual clarity and problem-solving abilities. Ensure that the questions are clearly worded and concise, aligned with NCERT guidelines to provide effective practice and support students in mastering the fundamentals of rotational motion.

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1 Answer

  1. The moment of inertia of a thin ring about a diameter is ๐ผ = 1/2MRยฒ , as derived using the perpendicular axis theorem.
    This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational motion. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/

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