A soft drink is available in two packs – (i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and (ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?

Length of tin can l = 5 cm, breadth b = 4 cm and height h = 15 cm
Volume of tin can = lbh = 5 × 4 × 15 = 300 cm³
Radius of plastic cylinder r = 7/2 = 3.5 cm and height H = 10 cm
Volume of plastic cylinder = πr²H
22/7 × 3.5 × 3.5 × 10 = 22 × 0.5 × 3.5 × 10 = 385 cm³
Difference between capacities of two packs = 385 – 300 = 85 cm³
Hence, the capacity of plastic cylindrical pack is greater than tin can by 85 cm³.