A rod of length 1.4 m and negligible mass has two masses of 0.3 kg and 0.7 kg tied to its two ends. Find the location of the point on this rod, where the rotational energy is minimum, when the rod is rotated about the point.
Energy is the capacity to do work or produce change, existing in various forms such as kinetic, potential, thermal and chemical.
Class 11 Physics
Systems of Particle & Rotational Motion
CBSE EXAM 2024-25
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One rod of 1.4 m length has the masses of 0.3 kg and 0.7 kg at both its ends, and its energy is determined while it is in rotational motion with a given rotational point. Let us determine this point for that given rod with respect to which it can have its rotational energy minimized if this rod is set in rotation at this particular point.
In this case, to find the point of optimal value, one must consider the mass distribution along the rod. In this scenario, the center of mass is of utmost importance, as it denotes the balance point of the system. If the rod rotates about its center of mass, the distances of each mass from that point determine the rotational energy.
The distances of the masses from the point of rotation can directly affect the moment of inertia. It would be perfect to have the axis of rotation closer to the larger mass if it is intended to reduce the rotational energy. Thus, in this configuration, the rotational energy is minimized at a distance of 0.98 meters from the 0.3 kg mass. This setup will make the system function very efficiently, bringing the energy necessary for rotation to a minimum.
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