A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

Internal radius of hemispherical bowl r = 5 cm and thickness = 0.25 cm
Therefore, the outer radius of hemispherical bowl = R = 5 + 0.25 = 5.25 cm
Outer curved surface area of hemispherical bowl = 2πR²
= 2 × 22/7 × 5.25 × 5.25 = 2 × 22 × 0.75 × 5.25 = 173.25 cm²
Hence, the outer curved surface area of hemispherical bowl is 173.25 cm².