Radius is 10 cm. (i) Minor sector area is (90/360) x 3.14 x 10² = (1/4) x 314 = 78.5 cm². (ii) Major sector area is (270/360) x 3.14 x 10² = (3/4) x 314 = 235.5 cm².
A chord of a circle of radius 10 cm subtends 90° at the centre. Find the area of the corresponding: (i) minor sector (that subtends 90° at the centre) and (ii) major sector (that subtends 270° at the centre). (Use π ≈ 3.14.)
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Given radius r = 10 cm and π = 3.14.
Total area of the circle = π x r² = 3.14 x 10² = 314 cm².
(i) For the minor sector, angle θ = 90°:
Area = (90 / 360) x π x r² = (1/4) x 314 = 78.5 cm².
(ii) For the major sector, angle θ = 360° – 90° = 270°:
Area = (270 / 360) x π x r² = (3/4) x 314 = 235.5 cm²
(or Total Area – Minor Sector Area = 314 – 78.5 = 235.5 cm²).
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/