In 60 minutes, the minute hand turns 360°, so in 10 minutes it turns (360/60) x 10 = 60°. The area swept is a sector: (60/360) x (22/7) x 7² = 77/3 = 25.67 cm².
The length of the minute hand of a clock is 7 cm. Find the area swept by the minute hand in 10 minutes.
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Length of the minute hand acts as the radius r = 7 cm.
The minute hand completes a full rotation of 360° in 60 minutes.
Angle swept in 1 minute = 360° / 60 = 6°.
Angle swept in 10 minutes:
θ = 10 x 6° = 60°.
The swept region is a circular sector with r = 7 cm and θ = 60°:
Area = (θ / 360) x π x r²
Area = (60 / 360) x (22/7) x 7 x 7 = (1/6) x 154 = 77 / 3 cm² = 25.67 cm².
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/