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Home/ Questions/Q 1515
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Nakul jha
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Nakul jha
Asked: October 29, 20202020-10-29T05:54:39+00:00 2020-10-29T05:54:39+00:00In: Class 10

A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears (i) a two-digit number (ii) a perfect square number (iii) a number divisible by 5.

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NCERT Solutions for Class 10 Maths Chapter 15
Important NCERT Questions
PROBABILITY
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 9.1
Page No:309
Questions No:18

2020-2021cbsechapter 15class10mathematicsncertprobability
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    1. Nadhir Sha
      2021-07-31T10:32:54+00:00Added an answer on July 31, 2021 at 10:32 am

      Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-15/

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      rishab17
      2023-02-28T07:16:10+00:00Added an answer on February 28, 2023 at 7:16 am

      Total number of discs = 90
      (i) Total number of two-digit numbers between 1 and 90 81
      P (getting a two-digit number) = 81/90 = 9/10
      (ii) Perfect squares between 1 and 90 are 1,4,9, 16, 25, 36, 49, 64, and 81.
      Therefore, total number of perfect squares between 1 and 90 is 9.
      P (getting a perfect square) = 9/90 = 1/10
      (iii) Numbers that are between 1 and 90 and divisible by 5 are 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 55, 60, 65, 70, 75, 80, 85, and 90.
      Therefore, total numbers divisible by 5 = 18
      Probability of getting a number divisible by 5 = 18/90 = 1/5

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