A body of mass 2 kg is placed on rough horizontal plane. The coefficient of friction between body and plane is 0.2 Then
A coefficient is a numerical value used to quantify relationships or properties in mathematics, physics, and science. It often represents proportionality or a constant factor in equations, such as the coefficient of friction indicating resistance between surfaces or coefficients in algebra expressing multiplication of variables in expressions or equations.
Chapter 5 of Class 11 Physics explores the concepts of work energy and power. It explains how work is calculated when a force is applied energy transformations the law of conservation of energy and different energy forms like kinetic and potential. The chapter also introduces power as the rate of performing work.
Share
To find the motion of the body placed on a rough horizontal plane, we need to consider the effects of friction and applied force.
Given:
Mass of the body (m) = 2 kg
Coefficient of friction (μ) = 0.2
Acceleration due to gravity (g) = 9.8 m/s² (we will use 10 m/s² for simplicity)
Step 1: Calculate the normal force (N)
On a horizontal plane, the normal force (N) is equal to the weight of the body:
N = m * g
N = 2 kg * 10 m/s²
N = 20 N
Step 2: Find the maximum static friction (f_s)
The maximum static friction is given by:
f_s = μ * N
f_s = 0.2 * 20 N
f_s = 4 N
Step 3: Analyze the applied force (F)
Case (a): If F = 5 N
– The applied force (5 N) is greater than the maximum static friction (4 N).
– Hence, the body will move in the forward direction.
Case (b): If F = 3 N
– The applied force (3 N) is less than the maximum static friction (4 N).
– Thus, the body will not move and will remain at rest.
**Case (c):** If F = 3 N
– Since the applied force is not enough to overcome friction, the body will remain at rest.
Conclusion:
– For F = 5 N, the body will move in the forward direction.
– For F = 3 N, the body will remain at rest.
– Hence, both (a) and (c) are correct.
Final Answer:
The correct options are both (a) and (c).
Click here for more:
https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-5/