Using area = (1/2) x base x height = 60 with base 10 cm gives height h = 12 cm. In the half-triangle right triangle with legs 5 cm and 12 cm, hypotenuse is √(5² + 12²) = 13 cm.
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The base is 40 – (15 + 15) = 10 cm. Semi-perimeter s = 20 cm. By Heron’s formula, area = √(20 x (20 – 15) x (20 – 15) x (20 – 10)) = √(20 x 5 x 5 ...
The minor sector area is (60/360) x π x r² = (1/6)πr². The triangle formed is equilateral with side r, giving area (√3/4)r². Subtracting yields segment area (1/6)πr² – (√3/4)r² = πr²(1/6 – √3/(4π)).
In 60 minutes, the minute hand turns 360°, so in 10 minutes it turns (360/60) x 10 = 60°. The area swept is a sector: (60/360) x (22/7) x 7² = 77/3 = 25.67 cm².
Circumference 2 x (22/7) x r = 44 yields radius r = 7 cm. A quadrant has angle 90°, so its area is (1/4) x π x r² = (1/4) x (22/7) x 7² = 77/2 = 38.5 cm².