Labeling fruits as A1, O1, O2 for basket A and B1, M1 for basket B gives 6 equally likely outcomes. The sample space is {(A1, B1), (A1, M1), (O1, B1), (O1, M1), (O2, B1), (O2, M1)}. P(Apple, Banana) = 1/6.
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In an illustrative 20-toss trial getting 11 heads and 9 tails, experimental probability of heads is 11 / 20 = 0.55. For the next toss, because a coin has no memory, tails probability remains 1 / 2 = 0.5.