(i) Primes 7 and 11 give 8 pairs, P = 8/36 = 2/9. (ii) P(different) = 1 – P(same) = 1 – 13/36 = 23/36. (iii) Favourable outcomes {HHT, HTH}, P = 2/8 = 1/4. (iv) Last digit 2 or 4, P = ...
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Total balls initially equal 9, reducing to 8 on the second draw without replacement. (i) P(Red then Blue) = (4/9) x (5/8) = 20/72 = 5/18. (ii) P(2 Blue) = (5/9) x (4/8) = 20/72 = 5/18.
The bag contains 3 distinct candies, giving a total of 3 possible outcomes. Since there is only 1 strawberry candy, the probability is 1 / 3 (approximately 0.333 or 33.3%).
The answers are: (i) 0, (ii) sample space, (iii) 1 and (iv) 1/2 (or 0.5). These represent fundamental probability values: 0 denotes impossibility, 1 indicates certainty and an unbiased coin yields an even chance of 0.5.
With replacement, total pens = 9. Outcomes for colors are RR, RB, RG, BR, BB, BG, GR, GB, GG. The probability of both picking the same color is P(RR) + P(BB) + P(GG) = 9/81 + 16/81 + 4/81 = ...