With replacement, tree branches into 4 paths then 4 paths each, creating 16 pairs (size 16). Without replacement, first draw branches into 4 paths then 3 paths each, creating 12 pairs (size 12).
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Total balls initially equal 9, reducing to 8 on the second draw without replacement. (i) P(Red then Blue) = (4/9) x (5/8) = 20/72 = 5/18. (ii) P(2 Blue) = (5/9) x (4/8) = 20/72 = 5/18.
With 2 shirt options and 3 pants choices, multiplying 2 x 3 produces 6 possible outfit combinations: (Red, Jeans), (Red, Khakis), (Red, Shorts), (Blue, Jeans), (Blue, Khakis) and (Blue, Shorts).
The correct term is relative frequency and its value is 15 / 50 = 3 / 10 = 0.3. While 15 is the absolute count (frequency), dividing by the total 50 students gives the relative frequency.
Labeling fruits as A1, O1, O2 for basket A and B1, M1 for basket B gives 6 equally likely outcomes. The sample space is {(A1, B1), (A1, M1), (O1, B1), (O1, M1), (O2, B1), (O2, M1)}. P(Apple, Banana) = 1/6.