This matches the three-term identity where the term containing variable b must be negative because both cross-product terms that include b have a minus sign in the expression.
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We split the middle coefficient minus 1 into minus 7 and positive 6 because their sum equals minus 1 and their product equals minus 42, giving the linear binomial factors.
This matches the three-term identity where the term containing variable b is negative because both cross-product terms that include b have a minus sign in the expression.
We separate 205 into 200 + 5 and use the addition square identity. Calculating the squares of both numbers and adding their double cross-product gives the final evaluation.
We express the product as (20 – 2) (30 – 1) and expand using the distributive property. Evaluating the separate numerical products step by step gives the clean final total.