We split 135 into 100 + 30 + 5 and expand it using the three-term identity. Summing the separate square values and their paired products provides the final answer.
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We split the middle term 7x into 3x plus 4x. Factoring the expressions in pairs gives the two linear binomial factors which are (2x + 1) and (3x + 2).
We split the middle term minus 4x into minus 7x plus 3x to factor the expression by grouping. Taking out common factors leaves (3x – 7) multiplied by (x + 1).
We substitute a = 3x, b = -2y and c = 4z into the expansion formula. Squaring terms makes them positive, while the cross-products involving the negative y term become negative.
This expression matches the identity template a square – 2ab + b square. The middle variable terms cancel out completely when multiplying p/4 and 4/p, leaving only the constant integer minus 2.