We split the middle term minus 11x into minus 15x plus 4x. Factoring by grouping yields the two expressions, filling the blanks with the number 3 and the term 5x.
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We split the middle coefficient minus 11 into minus 3 and minus 8 because their sum equals minus 11 and their product equals positive 24. This gives the factors directly.
We expand this by substituting a = p, b = 3q and c = 7r into the identity. Squaring the individual items and finding their paired double products yields the answer.
This six-term polynomial matches the expanded three-term identity. The squared bases are m/3, k/2, and 3n, which merge into the single grouped factor (m/3 + k/2 + 3n) square.
We treat 1120 as 1100 + 20 and apply the standard two-term addition square identity. Squaring both parts and adding their double product provides the final answer.